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Longest pole that fits in a box 3 ft by 4 ft by 10 ft

Step by step, with the reason for every step · Pythagoras in 3D · Geometry

Step by step

The question

Question: what is the longest pole that fits in a box 3 ft by 4 ft by 10 ft?

box 3 ft by 4 ft by 10 ft

The longest thing that fits goes from a bottom corner to the top corner on the other side: the diagonal through the box.

1 Floor diagonal

First the floor.

Its diagonal d makes a right triangle with the sides 3 and 4.

Pythagoras: d squared is 3 squared plus 4 squared.

3 times 3 is 9.

4 times 4 is 16.

Together 25.

d2 = 32 + 42 = 9 + 16 = 25
a² + b² = c²

5 times 5 is 25.

So d is 5.

d = √25 = 5

Careful!

We cannot just add the sides.

A diagonal is a short cut: Pythagoras, twice.

Careful: not 3 + 4 + 10 = 17 ✗

2 Diagonal of the box

Now a new right triangle stands up: the floor diagonal d, the height 10, and the diagonal D of the box.

Pythagoras again: D squared is d squared plus 10 squared.

d squared is 25.

10 times 10 is 100.

Together 125.

D2 = d2 + 102 = 25 + 100 = 125

125 is not a square number.

A calculator gives 11.180, and so on.

D = √125 = 11.180…

To the nearest tenth, D is about 11.2 ft.

D ≈ 11.2 ft

3 Check

Let's check: the two steps are the same as l squared plus w squared plus h squared.

9 plus 16 plus 100 is 125, the same D squared.

So the answer is right!

3² + 4² + 10² = 9 + 16 + 100 = 125

Let's look back.

First: floor diagonal.

Then: diagonal of the box.

Last: check.

Answer
D ≈ 11.2 ft

Your turn

Try this one yourself, then check:

box 4 ft by 3 ft by 7 ft
Show the answer
D ≈ 8.6 ft

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