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Diagonal of a box 4 by 5 by 6

Step by step, with the reason for every step · Pythagoras in 3D · Geometry

Step by step

The question

Question: find the diagonal of a box 4 by 5 by 6.

box 4 by 5 by 6

The diagonal goes from a bottom corner to the top corner on the other side, right through the box.

1 Floor diagonal

First the floor.

Its diagonal d makes a right triangle with the sides 4 and 5.

Pythagoras: d squared is 4 squared plus 5 squared.

4 times 4 is 16.

5 times 5 is 25.

Together 41.

d2 = 42 + 52 = 16 + 25 = 41
a² + b² = c²

41 is not a square number.

We do not need d itself: the next step uses d squared.

keep d² = 41

Careful!

We cannot just add the sides.

A diagonal is a short cut: Pythagoras, twice.

Careful: not 4 + 5 + 6 = 15 ✗

2 Diagonal of the box

Now a new right triangle stands up: the floor diagonal d, the height 6, and the diagonal D of the box.

Pythagoras again: D squared is d squared plus 6 squared.

d squared is 41.

6 times 6 is 36.

Together 77.

D2 = d2 + 62 = 41 + 36 = 77

77 is not a square number.

A calculator gives 8.775, and so on.

D = √77 = 8.775…

To the nearest tenth, D is about 8.8.

D ≈ 8.8

3 Check

Let's check: the two steps are the same as l squared plus w squared plus h squared.

16 plus 25 plus 36 is 77, the same D squared.

So the answer is right!

4² + 5² + 6² = 16 + 25 + 36 = 77

Let's look back.

First: floor diagonal.

Then: diagonal of the box.

Last: check.

Answer
D ≈ 8.8

Your turn

Try this one yourself, then check:

box 8 by 1 by 2
Show the answer
D ≈ 8.3

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