Steply

Domain of f(x) = 1/(2x - 3)

Step by step, with the reason for every step · Domain and range · Algebra 2

Step by step

The question

Question: find the domain of f(x) = 1/(2x − 3).

f(x) = 12x − 3

The domain is all the x's we can put in.

domain = the x's that can go in

1 Find where the bottom is 0

We can never divide by 0.

So the bottom of the fraction can never be 0.

÷ 0: not allowed

Which x makes the bottom 0?

We solve 2x − 3 = 0.

2x − 3 = 0

We want x by itself.

Two things are stuck to x: times 2 and − 3.

The − 3 is on the outside, so it comes off first.

Then the times 2.

2 Remove the − 3

To remove − 3, we add 3.

We do it on both sides, so they stay equal.

2x − 3 + 3 = 0 + 3

− 3 and + 3 make zero.

Cross them out.

0 + 3 = 3.

0 + 3 = 3

Now we have 2x = 3.

2x = 3

3 Remove the 2

2x means 2 times x.

We want just x.

To remove times 2, we divide by 2.

We do it on both sides, so they stay equal.

2x2 = 32

2 divided by 2 is 1.

So just x is left.

So x = 3/2!

x = 32

4 Write the domain

x = 3/2 is the only x that is not allowed.

The domain is all real numbers except 3/2: x ≠ 3/2.

x ≠ 32

5 Show it on a number line

Books also write the answer like this.

It is called interval notation.

A round bracket means the end is not in, like the open circle.

∞ means it goes on for ever.

∪ means or.

interval: (−∞, 32) ∪ (32, ∞)

Let's look back.

First: find where the bottom is 0.

Then: remove the − 3.

Then: remove the 2.

Then: write the domain.

Last: show it on a number line.

Answer
x ≠ 32

Your turn

Try this one yourself, then check:

domain of f(x) = 13x − 8
Show the answer
domain: x ≠ 83

More from Domain and range

The whole lesson: Domain and range →