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Domain of f(x) = √(x + 4)

Step by step, with the reason for every step · Domain and range · Algebra 2

Step by step

The question

Question: find the domain of f(x) = √(x + 4).

f(x) = √x + 4

The domain is all the x's we can put in.

domain = the x's that can go in

1 The inside is 0 or more

No real number times itself is negative.

3 times 3 is 9.

Minus 3 times minus 3 is 9 too.

So we can't take the square root of a negative number.

√ of a negative: not allowed
3 × 3 = 9, (−3) × (−3) = 9

So the inside, x + 4, must be 0 or more.

x + 4 ≥ 0

2 Remove the + 4

We want x by itself.

The + 4 is in the way.

To remove + 4, we take away 4.

We do it on both sides, so the sign stays true.

x + 4 − 4 ≥ 0 − 4

+ 4 and − 4 make zero.

Cross them out.

0 − 4 = −4.

0 − 4 = −4

So x is greater than or equal to −4.

x ≥ −4

These are the x's that can go in.

So the domain is x ≥ −4.

3 Show it on a number line

Books also write the answer like this.

It is called interval notation.

A square bracket means the end is in, like the filled circle.

∞ means it goes on for ever.

interval: [−4, ∞)

4 Check

Let's check.

Put −5 in, just outside.

The inside is −1: negative.

Not allowed.

x = −5: √−5 + 4 = √−1 not allowed

Now −3, inside: the inside is 1, and the square root of 1 is 1.

It works.

x = −3: √−3 + 4 = √1 = 1

Let's look back.

First: the inside is 0 or more.

Then: remove the + 4.

Then: show it on a number line.

Last: check.

Answer
x ≥ −4

Your turn

Try this one yourself, then check:

domain of f(x) = √x + 3
Show the answer
domain: x ≥ −3

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