Steply

Double integral of 1 over the region between y = x^2 and y = 4

Step by step, with the reason for every step · Double integrals over general regions · Calculus 3

Step by step

The question

Question: find the double integral of 1 over the region between y = x² and y = 4.

∫ ∫ 1 dA, between y = x² and y = 4

1 Draw the region

Draw the grid.

Draw y = 4

and y = x².

The region is between them.

Where do they meet?

Where the two heights are equal.

4 = x2

Bring everything to one side.

4 − x2 = 0

Move the number and divide: x² = 4.

x2 = 4

So they meet at x = −2 and x = 2.

x = −2 or x = 2

Which is on top?

Try x = 0: y = 4 is higher.

x = 0: 4 → 4, x² → 0

2 Find the limits

Take a thin upright strip.

On it, y goes from the bottom curve up to the top curve.

So inside, y goes from x² to 4.

Outside, x goes from −2 to 2.

∫ ∫ 1 dA = ∫ from −2 to 2 of ∫ from x² to 4 of 1 dy dx

Careful!

The inside integral is dy, so its limits are the y limits.

They may have x in them.

The outside limits are only numbers.

Careful: dy inside: the y limits go inside

3 The inner integral

Inside first: integrate in y.

x stays fixed, like a plain number.

Integrate each term: the power goes up by 1, and we divide by the new power.

∫ from x² to 4 of 1 dy = y from x² to 4

Put in the top y = 4, then take away the bottom y = x².

∫ from x² to 4 of 1 dy = (4) − (x2)

So it is 4 − x².

∫ from x² to 4 of 1 dy = 4 − x2

4 The outer integral

Now the outside integral, in x.

Its limits are numbers.

Integrate each term: the power goes up by 1, and we divide by the new power.

∫ from −2 to 2 of (4 − x2) dx = [4x − x33] from −2 to 2

Put in the top x = 2, then take away the bottom x = −2.

∫ from −2 to 2 of (4 − x2) dx = (4(2) − (2)33) − (4(−2) − (−2)33)

So it is 32/3.

∫ from −2 to 2 of (4 − x2) dx = 323

5 Check

Let's check if it makes sense.

The region's area is 32/3.

On it, f goes from 1 to 1.

area = 32/3, f from 1 to 1

So the answer must be between 10.667 and 10.667.

10.667 is.

Right!

10.667 ≤ 10.667 ≤ 10.667

Let's look back.

First: draw the region.

Then: find the limits.

Then: the inner integral.

Then: the outer integral.

Last: check.

Answer
∫ from −2 to 2 of (4 − x2) dx = 323

Your turn

Try this one yourself, then check:

∫ ∫ 2 dA, between y = x² and y = 4
Show the answer
643

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