Steply

Double integral of 2 over the region between y = x^2 - 1 and y = 1 -…

Step by step, with the reason for every step · Double integrals over general regions · Calculus 3

Step by step

The question

Question: find the double integral of 2 over the region between y = x² − 1 and y = 1 − x².

∫ ∫ 2 dA, between y = x² − 1 and y = 1 − x²

1 Draw the region

Draw the grid.

Draw y = 1 − x²

and y = x² − 1.

The region is between them.

Where do they meet?

Where the two heights are equal.

1 − x2 = x2 − 1

Bring everything to one side.

2 − 2x2 = 0

Move the number and divide: x² = 1.

x2 = 1

So they meet at x = −1 and x = 1.

x = −1 or x = 1

Which is on top?

Try x = 0: y = 1 − x² is higher.

x = 0: 1 − x² → 1, x² − 1 → −1

2 Find the limits

Take a thin upright strip.

On it, y goes from the bottom curve up to the top curve.

So inside, y goes from x² − 1 to 1 − x².

Outside, x goes from −1 to 1.

∫ ∫ 2 dA = ∫ from −1 to 1 of ∫ from x² − 1 to 1 − x² of 2 dy dx

Careful!

The inside integral is dy, so its limits are the y limits.

They may have x in them.

The outside limits are only numbers.

Careful: dy inside: the y limits go inside

3 The inner integral

Inside first: integrate in y.

x stays fixed, like a plain number.

Integrate each term: the power goes up by 1, and we divide by the new power.

∫ from x² − 1 to 1 − x² of 2 dy = 2y from x² − 1 to 1 − x²

Put in the top y = 1 − x², then take away the bottom y = x² − 1.

∫ from x² − 1 to 1 − x² of 2 dy = 2(1 − x2) − 2(x2 − 1)

Work out each part.

∫ from x² − 1 to 1 − x² of 2 dy = 2 − 2x2 − 2x2 − 2

So it is 4 − 4x².

∫ from x² − 1 to 1 − x² of 2 dy = 4 − 4x2

4 The outer integral

Now the outside integral, in x.

Its limits are numbers.

Integrate each term: the power goes up by 1, and we divide by the new power.

∫ from −1 to 1 of (4 − 4x2) dx = [4x − 4x33] from −1 to 1

Put in the top x = 1, then take away the bottom x = −1.

∫ from −1 to 1 of (4 − 4x2) dx = (4(1) − 4(1)33) − (4(−1) − 4(−1)33)

So it is 16/3.

∫ from −1 to 1 of (4 − 4x2) dx = 163

5 Check

Let's check if it makes sense.

The region's area is 8/3.

On it, f goes from 2 to 2.

area = 8/3, f from 2 to 2

So the answer must be between 5.333 and 5.333.

5.333 is.

Right!

5.333 ≤ 5.333 ≤ 5.333

Let's look back.

First: draw the region.

Then: find the limits.

Then: the inner integral.

Then: the outer integral.

Last: check.

Answer
∫ from −1 to 1 of (4 − 4x2) dx = 163

Your turn

Try this one yourself, then check:

∫ ∫ 4 dA, between y = x² − 1 and y = 1 − x²
Show the answer
323

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