Steply

Evaluate ∫ from 1 to 4 of 6/(2x + 1) dx

Step by step, with the reason for every step · Integrals with e and ln · Calculus 2

Step by step

The question

Question: find the integral from 1 to 4 of 6/(2x + 1).

∫ from 1 to 4 of 62x + 1 dx =

1 The rules

Now 1 over x.

The power rule cannot do it: x to the −1 would become x to the 0, over 0.

Instead: the derivative of ln x is 1 over x.

So the integral of 1/x is ln|x| + C.

∫ 1x dx = ln|x| + C

The bars mean the size of x.

ln only takes positive numbers, and x may be negative.

|x|: ln needs a number > 0

With 2x + 1 at the bottom: ln of the bottom, divided by 2.

Its derivative would bring a 2 out, by the chain rule.

∫ 12x + 1 dx = 12ln|2x + 1| + C

Careful!

The power rule fails for 1/x: the new power would be 0, and we cannot divide by 0.

Use ln.

Careful: not x00 ✗

2 Integrate

Divide by 2: 6/2 is 3.

No + C: we work out top minus bottom.

∫ from 1 to 4 of 62x + 1 dx = [ 3ln|2x + 1| ] from 1 to 4

3 Top minus bottom

Put in 4, then take away the same with 1.

= 3ln 9 − 3ln 3

Two logs taken away make one log of a fraction.

ln a − ln b = ln ab

So the integral is 3 ln 3.

A calculator gives about 3.296.

= 3ln 3 ≈ 3.296

4 Check

Let's check with a calculator: it adds up 1000 thin strips.

That gives about 3.296, the same as our answer.

Right!

1000 thin strips: ≈ 3.296

Let's look back.

First: the rules.

Then: integrate.

Then: top minus bottom.

Last: check.

Answer
= 3ln 3 ≈ 3.296

Your turn

Try this one yourself, then check:

∫ from 1 to 4 of 42x + 1 dx
Show the answer
2ln 3 ≈ 2.197

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