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Graph x = 3 cos t, y = 3 sin t

Step by step, with the reason for every step · Parametric equations · Precalculus

Step by step

The question

Question: graph and remove t from x = 3 cos t, y = 3 sin t.

x = 3 cos t and y = 3 sin t

1 Make a table

At 0°, 90°, 180°, 270° and 360°, cos and sin are easy: 1, 0 or −1.

They are the x and y of a point going round a circle of radius 1.

cos: 1, 0, −1, 0, 1 sin: 0, 1, 0, −1, 0

Take t = 0°, 90°, 180°, 270° and 360°.

x is 3 times cos t,

3
0
−3
0
3

and y is 3 times sin t.

0
3
0
−3
0

2 Plot the points

Draw the grid.

Put each (x, y) on the grid.

At 360° we are back at the start.

3 Join in order of t

Join them in order of t: it goes round, against the clock.

A circle.

4 Remove t

For every t: cos² t + sin² t = 1.

It is Pythagoras on the circle of radius 1: across cos t, up sin t, long side 1.

cos²t + sin²t = 1

Get cos t alone: divide x by 3.

x3 = cos t

And sin t: divide y by 3.

y3 = sin t

Square both and add them.

(x3)2 + (y3)2 = cos²t + sin²t

Careful!

Not cos t plus sin t: that is not always 1.

Only the squares add up to 1.

Careful: square first, then add

That is 1, for every t.

So t is gone.

(x3)2 + (y3)2 = 1

Each square is 9 at the bottom.

Multiply both sides by 9: x² + y² = 9.

A circle of radius 3.

x2 + y2 = 9
× 9: x²9 × 9 = x²

5 Check

Let's check with t = 90°: the point (0, 3).

Put it in the answer: we get 9, the right side.

Right!

0² + 3² = 9

Let's look back.

First: make a table.

Then: plot the points.

Then: join in order of t.

Then: remove t.

Last: check.

Answer
× 9: x²9 × 9 = x²

Your turn

Try this one yourself, then check:

x = 2 cos t, y = 2 sin t
Show the answer
x2 + y2 = 4

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