Steply

Graph x = t + 1, y = t^2 for 0 ≤ t ≤ 3

Step by step, with the reason for every step · Parametric equations · Precalculus

Step by step

The question

Question: graph and remove t from x = t + 1, y = t², for 0 ≤ t ≤ 3.

x = t + 1 and y = t2

1 Make a table

Each t gives a point.

Start with t = 0.

x is 0 + 1: 1.

t = 0: x = 0 + 1 = 1

y is 0²: 0.

y = 0² = 0

Put the t's in a table: t from 0 to 3.

Work out x for each t,

1
2
3
4

and y for each t.

0
1
4
9

2 Plot the points

Draw the grid.

Put each (x, y) on the grid.

3 Join in order of t

Join the points in order: t = 0, then 1, and on.

The arrows show the way t grows.

4 Remove t

To get t alone, start with x = t + 1.

To remove + 1, we take away 1.

We do it on both sides, so they stay equal.

x − 1 = t + 1 − 1

So t = x − 1.

t = x − 1

Put t into y = t², with its bracket: y = (x − 1)².

y = (x − 1)2

Careful!

The whole of x − 1 is squared, not only the last number.

So it keeps its bracket.

Careful: not y = x − 1² ✗

5 Check

Let's check with a point from the table: t = 3 gave (4, 9).

Put x = 4 into the answer.

We get y = 9, the same as the table.

Right!

x = 4: y = (4 − 1)² = 9

Let's look back.

First: make a table.

Then: plot the points.

Then: join in order of t.

Then: remove t.

Last: check.

Answer
Careful: not y = x − 1² ✗

Your turn

Try this one yourself, then check:

x = t + 3, y = t², for 0 ≤ t ≤ 3
Show the answer
y = (x − 3)2

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