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Inflection points of f(x) = x^3 - 6x^2 + 4

Step by step, with the reason for every step · Concavity and inflection points · Calculus 1

Step by step

The question

Question: find the concavity and the inflection points of f(x) = x³ − 6x² + 4.

f(x) = x3 − 6x2 + 4

Concave up means the curve bends up, like a cup.

That is where f″ is positive.

Concave down bends down, like a cap: f″ is negative.

cup concave up: f″ > 0
cap concave down: f″ < 0

1 Find f″(x)

First f′: the power rule on each term.

f′(x) = 3x^(3 − 1) − 6 × 2x^(2 − 1) + 0

Now we have f′(x) = 3x² − 12x.

= 3x2 − 12x

Then f″: the power rule again, on f′.

f″(x) = 3 × 2x^(2 − 1) − 12 × 1

Now we have f″(x) = 6x − 12.

= 6x − 12

2 Solve f″(x) = 0

The bending can only change where f″ is 0.

So we solve f″(x) = 0.

f″(x) = 0
6x − 12 = 0

Take out the 6.

6(x − 2) = 0

So x = 2.

x = 2

3 Sign table for f″

A sign table for f″.

The number 2 cuts the line into 2 parts.

Test one number in each part: 1, 3.

f″(1) = −6, f″(3) = 6

f″(1) is −6: negative.

So f bends down there: a cap.

cap

f″(3) is 6: positive.

So f bends up there: a cup.

cup
0

Careful!

Concave up is about the bending, not about going up.

A cup can go down on one side.

Careful: concave up is not "going up"

4 Inflection points

At x = 2, the bending changes: an inflection point.

infl.

Its y: put 2 into f.

We get −12.

f(2) = 23 − 6(2)2 + 4 = 8 − 24 + 4 = −12

f is concave up where f″ is positive: x > 2.

up ∪ : x > 2

f is concave down where f″ is negative: x < 2.

down ∩ : x < 2

And the inflection point is (2, −12).

inflection : (2, −12)

5 Check

Let's check with the graph.

A cap, then a cup.

It changes at the inflection point.

Right!

Let's look back.

First: find f″(x).

Then: solve f″(x) = 0.

Then: sign table for f″.

Then: inflection points.

Last: check.

Answer
inflection : (2, −12)

Your turn

Try this one yourself, then check:

Find the concavity and the inflection points of f(x) = x3 + 6x2 + 4x + 2
Show the answer
concave up: x > −2; concave down: x < −2; inflection: (−2, 10)

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