Steply

Limit as x -> infinity of (3x - 4)/(x^2 + 1)

Step by step, with the reason for every step · Limits at infinity · Calculus

Step by step

The question

Question: find the limit as x → ∞ of (3x − 4)/(x² + 1).

lim x → ∞ 3x − 4x2 + 1 =

1 Find the highest powers

x goes to infinity: x gets huge, bigger than any number.

Then the highest power wins.

On top it is 3x.

At the bottom it is x².

See it with x = 1000.

3x is 3,000.

The other part is tiny next to that.

x = 1000: 3x = 3,000
−4: tiny next to it

2 Keep only those

So we keep only 3x/x².

= lim x → ∞ 3xx × x

Split the bigger power: x² is x × x.

x² = x × x

x/x is 1.

Cross them out.

Write what is left.

x is still at the bottom.

= lim x → ∞ 3x

3/a huge number is tiny.

As x grows, it gets closer and closer to 0.

x = 1000: 3 ÷ 1,000 = 0.003

Careful!

The bottom grows faster than the top.

So the fraction gets smaller and smaller.

Careful: top power smaller → 0

So the limit is 0.

= 0

3 Check

Let's check: put x = 1000 into the whole fraction.

A calculator gives about 0.003.

x = 1000: f(x) ≈ 0.0030

With x = 10000 it is even closer to 0.

Right!

x = 10000: f(x) ≈ 0.0003

Let's look back.

First: find the highest powers.

Then: keep only those.

Last: check.

Answer
= 0

Your turn

Try this one yourself, then check:

lim x → ∞ 5x − 8x2 + 1
Show the answer
limit = 0

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