Steply

Limit as x -> infinity of (4x^2 - x)/(2x^2 + 7)

Step by step, with the reason for every step · Limits at infinity · Calculus

Step by step

The question

Question: find the limit as x → ∞ of (4x² − x)/(2x² + 7).

lim x → ∞ 4x2 − x2x2 + 7 =

1 Find the highest powers

x goes to infinity: x gets huge, bigger than any number.

Then the highest power wins.

On top it is 4x².

At the bottom it is 2x².

See it with x = 1000.

4x² is 4,000,000.

The other part is tiny next to that.

x = 1000: 4x² = 4,000,000
−x: tiny next to it

2 Keep only those

So we keep only 4x² over 2x².

= lim x → ∞ 4x²2x²

x² over x² is 1.

Cross them out.

Only the numbers are left: 4/2.

They do not change when x grows.

= 42

4 divided by 2 is 2.

So the limit is 2.

= 2

3 Check

Let's check: put x = 1000 into the whole fraction.

A calculator gives about 1.9995.

x = 1000: f(x) ≈ 1.9995

With x = 10000 it is even closer to 2.

Right!

x = 10000: f(x) ≈ 1.9999

Let's look back.

First: find the highest powers.

Then: keep only those.

Last: check.

Answer
= 2

Your turn

Try this one yourself, then check:

lim x → ∞ 4x2 − x2x2 + 5
Show the answer
limit = 2

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