Steply

Limit as x -> infinity of 5/(x^2 + 1)

Step by step, with the reason for every step · Limits at infinity · Calculus

Step by step

The question

Question: find the limit as x → ∞ of 5/(x² + 1).

lim x → ∞ 5x2 + 1 =

1 Find the highest powers

x goes to infinity: x gets huge, bigger than any number.

Then the highest power wins.

On top it is 5.

At the bottom it is x².

2 Keep only those

So we keep only 5/x².

= lim x → ∞ 5x⁰x⁰ × x²

Split the bigger power: x² is x⁰ × x².

x² = x⁰ × x²

x⁰ over x⁰ is 1.

Cross them out.

Write what is left.

x² is still at the bottom.

= lim x → ∞ 5x²

5/a huge number is tiny.

As x grows, it gets closer and closer to 0.

x = 1000: 5 ÷ 1,000,000 = 0.000005

Careful!

The bottom grows faster than the top.

So the fraction gets smaller and smaller.

Careful: top power smaller → 0

So the limit is 0.

= 0

3 Check

Let's check: put x = 1000 into the whole fraction.

A calculator gives about 0.

x = 1000: f(x) ≈ 0.0000

With x = 10000 it is even closer to 0.

Right!

x = 10000: f(x) ≈ 0.0000

Let's look back.

First: find the highest powers.

Then: keep only those.

Last: check.

Answer
= 0

Your turn

Try this one yourself, then check:

lim x → ∞ 8x2 + 1
Show the answer
limit = 0

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