Steply

Limit as x -> infinity of (6x - 1)/(3x + 2)

Step by step, with the reason for every step · Limits at infinity · Calculus

Step by step

The question

Question: find the limit as x → ∞ of (6x − 1)/(3x + 2).

lim x → ∞ 6x − 13x + 2 =

1 Find the highest powers

x goes to infinity: x gets huge, bigger than any number.

Then the highest power wins.

On top it is 6x.

At the bottom it is 3x.

See it with x = 1000.

6x is 6,000.

The other part is tiny next to that.

x = 1000: 6x = 6,000
−1: tiny next to it

2 Keep only those

So we keep only 6x/3x.

= lim x → ∞ 6x3x

x/x is 1.

Cross them out.

Careful!

Not −1/2, the plain numbers!

They matter when x is near 0.

Not when x is huge.

Careful: not −12 ✗

Only the numbers are left: 6/3.

They do not change when x grows.

= 63

6 divided by 3 is 2.

So the limit is 2.

= 2

3 Check

Let's check: put x = 1000 into the whole fraction.

A calculator gives about 1.9983.

x = 1000: f(x) ≈ 1.9983

With x = 10000 it is even closer to 2.

Right!

x = 10000: f(x) ≈ 1.9998

Let's look back.

First: find the highest powers.

Then: keep only those.

Last: check.

Answer
= 2

Your turn

Try this one yourself, then check:

lim x → ∞ 8x − 14x + 3
Show the answer
limit = 2

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