Steply

Magnitude of <2, 2, 4>

Step by step, with the reason for every step · Vectors in space · Calculus 3

Step by step

The question

Question: find the length of v = ⟨2, 2, 4⟩.

v = ⟨2, 2, 4⟩

1 Draw it

Draw the three axes.

The arrow starts at the origin.

Go 2 along x, 2 along y, 4 along z.

The arrow goes from the origin to the end of that path.

2 Find the length

The length ‖v‖ is Pythagoras with three parts.

Square each part, add, then take the square root.

‖v‖ = √22 + 22 + 42

2 squared is 4.

2 squared is 4.

4 squared is 16.

‖v‖ = √4 + 4 + 16

Add: 4 plus 4 plus 16 is 24.

‖v‖ = √24

But 24 has a square number in it: 4.

24 is 4 times 6.

‖v‖ = √4 × 6

A root of a times splits into two roots.

‖v‖ = √4 × √6

√4 is 2.

2 × 2 = 4

So ‖v‖ = 2√6.

That is the exact answer, made simple.

‖v‖ = 2√6

With a calculator, that is about 4.9, to the nearest tenth.

‖v‖ ≈ 4.9

Careful!

We don't add the parts.

The arrow is the long side of a right triangle, so we square, add, and take the root.

Careful: not ‖v‖ = 2 + 2 + 4 ✗

3 Check

Let's check it as Pythagoras twice.

Across the floor the square is 8.

Then up z: 8 plus 16 is 24.

The same!

floor: 4 + 4 = 8, then 8 + 16 = 24

Let's look back.

First: draw it.

Then: find the length.

Last: check.

Answer
Careful: not ‖v‖ = 2 + 2 + 4 ✗

Your turn

Try this one yourself, then check:

Find the length of v = ⟨1, 1, 3⟩
Show the answer
‖v‖ = √11 ≈ 3.3

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