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Mean and sd of the sample mean: mean 50, sd 12, n 36

Step by step, with the reason for every step · Sample means and the central limit theorem · University Statistics

Step by step

The question

Question: samples of 36 are taken from numbers with mean 50 and SD 12: find the mean and the SD of the sample means.

μ = 50, σ = 12, n = 36: mean and SD of x̄?

The central limit theorem: the means of many samples make a bell.

many samples of 36: their means make a bell

1 The center

Its middle is the same as the numbers' mean: 50.

μx̄ = μ = 50

2 The spread

Means of samples are closer together than single numbers.

Their SD is σ divided by the square root of n.

means are less spread out: SD = σ ÷ √n

The square root of 36 is 6.

12 divided by 6 is 2.

σx̄ = σ√n = 12√36 = 126 = 2

Careful!

We divide by the square root of 36, not by 36.

Careful: divide by √n, not by n

The bell of the sample means: middle 50, one SD is 2.

3 Check

Let's check: times the square root of 36 takes us back.

2 times 6 is 12, the SD σ.

So it is right!

2 × √36 = 2 × 6 = 12

Let's look back.

First: the center.

Then: the spread.

Last: check.

Answer
Careful: divide by √n, not by n

Your turn

Try this one yourself, then check:

μ = 90, σ = 30, n = 100: mean and SD of x̄?
Show the answer
μx̄ = 90, σx̄ = 3

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