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Samples of 64 from mean 20, sd 4: P(sample mean < 19.5)

Step by step, with the reason for every step · Sample means and the central limit theorem · University Statistics

Step by step

The question

Question: samples of 64 are taken from numbers with mean 20 and SD 4: what is the probability that the sample mean is less than 19.5?

P(x̄ < 19.5): μ = 20, σ = 4, n = 64

x̄, x bar, is the mean of one sample.

x̄ = the mean of one sample

1 The sample means

The central limit theorem: the means of many samples make a bell.

Its middle is the mean, 20.

Its SD is smaller: σ divided by the square root of n.

many samples of 64: their means make a bell
middle: μ = 20
SD of the means: σ ÷ √n

The square root of 64 is 8.

4 divided by 8 is 0.5.

σx̄ = σ√n = 4√64 = 48 = 0.5

Careful!

The sample means have SD 0.5, not 4.

So we divide by 0.5.

Careful: not z = 19.5 − 204 ✗

2 Find z

z counts how many SDs the sample mean is from the mean: x̄ minus the mean, over the SD.

z = x̄ − μσx̄

19.5 minus 20 is −0.5.

Divided by 0.5, that is −1.

z = 19.5 − 200.5 = −0.50.5 = −1

3 Draw and shade

The bell: the mean, 20, in the middle.

19.5 is left of it.

We want the sample mean less than 19.5.

We shade that part.

4 Read the table

The z-table gives the area to the left of z.

Row −1.0, column .00.

For z = −1: the row −1.0 and the column .00 meet at 0.1587.

5 The area we want

Less than: the area to the left.

That is just the table number, 0.1587.

P(x̄ < 19.5) = 0.1587

6 Check

Let's check another way.

The bell is the same on both sides.

So the area left of −1 is the area right of 1.

left of −1 = right of 1

1 minus the table at 1: 1 minus 0.8413 is 0.1587.

The same!

So it is right!

1 − table at 1: 1 − 0.8413 = 0.1587

Let's look back.

First: the sample means.

Then: find z.

Then: draw and shade.

Then: read the table.

Then: the area we want.

Last: check.

Answer
P(x̄ < 19.5) = 0.1587

Your turn

Try this one yourself, then check:

Find P(x̄ < 24.5): μ = 25, σ = 4, n = 64
Show the answer
P(x̄ < 24.5) = 0.1587

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