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Samples of 100 from mean 500, sd 50: P(sample mean > 510)

Step by step, with the reason for every step · Sample means and the central limit theorem · University Statistics

Step by step

The question

Question: samples of 100 are taken from numbers with mean 500 and SD 50: what is the probability that the sample mean is more than 510?

P(x̄ > 510): μ = 500, σ = 50, n = 100

x̄, x bar, is the mean of one sample.

x̄ = the mean of one sample

1 The sample means

The central limit theorem: the means of many samples make a bell.

Its middle is the mean, 500.

Its SD is smaller: σ divided by the square root of n.

many samples of 100: their means make a bell
middle: μ = 500
SD of the means: σ ÷ √n

The square root of 100 is 10.

50 divided by 10 is 5.

σx̄ = σ√n = 50√100 = 5010 = 5

Careful!

The sample means have SD 5, not 50.

So we divide by 5.

Careful: not z = 510 − 50050 ✗

2 Find z

z counts how many SDs the sample mean is from the mean: x̄ minus the mean, over the SD.

z = x̄ − μσx̄

510 minus 500 is 10.

Divided by 5, that is 2.

z = 510 − 5005 = 105 = 2

3 Draw and shade

The bell: the mean, 500, in the middle.

510 is right of it.

We want the sample mean more than 510.

We shade that part.

4 Read the table

The z-table gives the area to the left of z.

Row 2.0, column .00.

For z = 2: the row 2.0 and the column .00 meet at 0.9772.

5 The area we want

The whole bell is 1.

The right side is 1 minus the left: 1 minus 0.9772 is 0.0228.

P(x̄ > 510) = 1 − 0.9772 = 0.0228

6 Check

Let's check another way.

The bell is the same on both sides.

So the area right of 2 is the area left of −2.

right of 2 = left of −2

The table at −2 gives 0.0228.

The same!

So it is right!

table at −2: 0.0228

Let's look back.

First: the sample means.

Then: find z.

Then: draw and shade.

Then: read the table.

Then: the area we want.

Last: check.

Answer
P(x̄ > 510) = 1 − 0.9772 = 0.0228

Your turn

Try this one yourself, then check:

Find P(x̄ > 550): μ = 520, σ = 150, n = 100
Show the answer
P(x̄ > 550) = 0.0228

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