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Samples of 16 from mean 70, sd 8: P(sample mean > 73)

Step by step, with the reason for every step · Sample means and the central limit theorem · University Statistics

Step by step

The question

Question: samples of 16 are taken from numbers with mean 70 and SD 8: what is the probability that the sample mean is more than 73?

P(x̄ > 73): μ = 70, σ = 8, n = 16

x̄, x bar, is the mean of one sample.

x̄ = the mean of one sample

1 The sample means

The central limit theorem: the means of many samples make a bell.

Its middle is the mean, 70.

Its SD is smaller: σ divided by the square root of n.

many samples of 16: their means make a bell
middle: μ = 70
SD of the means: σ ÷ √n

The square root of 16 is 4.

8 divided by 4 is 2.

σx̄ = σ√n = 8√16 = 84 = 2

Careful!

The sample means have SD 2, not 8.

So we divide by 2.

Careful: not z = 73 − 708 ✗

2 Find z

z counts how many SDs the sample mean is from the mean: x̄ minus the mean, over the SD.

z = x̄ − μσx̄

73 minus 70 is 3.

Divided by 2, that is 1.5.

z = 73 − 702 = 32 = 1.5

3 Draw and shade

The bell: the mean, 70, in the middle.

73 is right of it.

We want the sample mean more than 73.

We shade that part.

4 Read the table

The z-table gives the area to the left of z.

Row 1.5, column .00.

For z = 1.5: the row 1.5 and the column .00 meet at 0.9332.

5 The area we want

The whole bell is 1.

The right side is 1 minus the left: 1 minus 0.9332 is 0.0668.

P(x̄ > 73) = 1 − 0.9332 = 0.0668

6 Check

Let's check another way.

The bell is the same on both sides.

So the area right of 1.5 is the area left of −1.5.

right of 1.5 = left of −1.5

The table at −1.5 gives 0.0668.

The same!

So it is right!

table at −1.5: 0.0668

Let's look back.

First: the sample means.

Then: find z.

Then: draw and shade.

Then: read the table.

Then: the area we want.

Last: check.

Answer
P(x̄ > 73) = 1 − 0.9332 = 0.0668

Your turn

Try this one yourself, then check:

Find P(x̄ > 79): μ = 70, σ = 24, n = 16
Show the answer
P(x̄ > 79) = 0.0668

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