Steply

Mean of grouped data 10-19: 2, 20-29: 5, 30-39: 8, 40-49: 4, 50-59: 1

Step by step, with the reason for every step · Mean of grouped data · Statistics

Step by step

The question

Question: find the mean of the grouped data with classes 10 to 19, 20 to 29, 30 to 39, 40 to 49 and 50 to 59, and frequencies 2, 5, 8, 4 and 1.

Mean of the grouped data

Each class is a range of numbers.

f is how many numbers are in it.

So 2 numbers are from 10 to 19.

f = how many, m = the middle of the class

1 Find the midpoints

We don't know the numbers themselves.

So each class uses its middle, m: the midpoint.

m = (10 + 19) ÷ 2 = 14.5

The middle of 10 and 19: add them, divide by 2.

14.5.

Next: 24.5.

Each midpoint is 10 more.

And so on.

2 Multiply m × f

Each number in a class counts as its midpoint.

So a class adds up to m times f.

14.5 times 2 is 29.

24.5 times 5 is 122.5.

The same for every row.

3 Add the columns

The f column: 20 numbers in all.

2 + 5 + 8 + 4 + 1 = 20

The m × f column: 660.

That is about the total of all the numbers.

29 + 122.5 + 276 + 178 + 54.5 = 660

4 Share equally

The mean shares the total equally: 660 divided by 20.

mean ≈ 66020

It is only an estimate: the midpoints stand in for the real numbers.

≈ : an estimate, from the midpoints

Careful!

Not divided by the 5 classes.

There are 20 numbers.

Careful: not 6605 ✗

660 divided by 20 is 33.

mean ≈ 33

5 Check

Let's check: 33 times 20 is 660, the total.

33 × 20 = 660

And the mean is between the first and the last midpoints.

So it makes sense!

14.5 < 33 < 54.5

Let's look back.

First: find the midpoints.

Then: multiply m × f.

Then: add the columns.

Then: share equally.

Last: check.

Answer
mean ≈ 33

Your turn

Try this one yourself, then check:

Mean of 30–39: 4, 40–49: 3, 50–59: 8, 60–69: 4, 70–79: 1
Show the answer
mean ≈ 52

More from Mean of grouped data

The whole lesson: Mean of grouped data →