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Mean of grouped data 40-50: 3, 50-60: 7, 60-70: 12, 70-80: 6, 80-90: 2

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Step by step

The question

Question: find the mean of the grouped data with classes 40 to 50, 50 to 60, 60 to 70, 70 to 80 and 80 to 90, and frequencies 3, 7, 12, 6 and 2.

Mean of the grouped data

Each class is a range of numbers.

f is how many numbers are in it.

So 3 numbers are from 40 to 50.

f = how many, m = the middle of the class

1 Find the midpoints

We don't know the numbers themselves.

So each class uses its middle, m: the midpoint.

m = (40 + 50) ÷ 2 = 45

The middle of 40 and 50: add them, divide by 2.

45.

Next: 55.

Each midpoint is 10 more.

And so on.

2 Multiply m × f

Each number in a class counts as its midpoint.

So a class adds up to m times f.

45 times 3 is 135.

55 times 7 is 385.

The same for every row.

3 Add the columns

The f column: 30 numbers in all.

3 + 7 + 12 + 6 + 2 = 30

The m × f column: 1920.

That is about the total of all the numbers.

135 + 385 + 780 + 450 + 170 = 1920

4 Share equally

The mean shares the total equally: 1920 divided by 30.

mean ≈ 192030

It is only an estimate: the midpoints stand in for the real numbers.

≈ : an estimate, from the midpoints

Careful!

Not divided by the 5 classes.

There are 30 numbers.

Careful: not 19205 ✗

1920 divided by 30 is 64.

mean ≈ 64

5 Check

Let's check: 64 times 30 is 1920, the total.

64 × 30 = 1920

And the mean is between the first and the last midpoints.

So it makes sense!

45 < 64 < 85

Let's look back.

First: find the midpoints.

Then: multiply m × f.

Then: add the columns.

Then: share equally.

Last: check.

Answer
mean ≈ 64

Your turn

Try this one yourself, then check:

Mean of 40–50: 6, 50–60: 4, 60–70: 14, 70–80: 8, 80–90: 4
Show the answer
mean ≈ 65

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