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Net of a square pyramid base 10, slant height 12

Step by step, with the reason for every step · Nets and surface area · Geometry

Step by step

The question

Question: draw the net of a square pyramid, base 10, slant height 12, and find its surface area.

square pyramid, base 10, slant height 12

The surface area is the area of all the outside faces together.

A net shows every face flat.

surface area = all the faces added

1 Unfold it

Flat: the square base, with a triangle on each side.

2 Area of each face

The square base: 10 × 10 is 100.

= the square base: 10 × 10 = 100

Each triangle: half × 10 × 12 is 60.

= each triangle: ½ × 10 × 12 = 60

Careful!

Count every face in the net.

There are four triangles.

Careful: not 100 + 60 = 160 ✗

3 Add them all

We add all 5 faces: 340.

= SA = 100 + 60 + 60 + 60 + 60 = 340

4 Check

Let's check another way.

Four triangles of half 10 times 12 are two whole 10 by 12 rectangles: 240.

Plus the base 100.

Together 340.

So the answer is right!

10 × 10 + 2 × 10 × 12 = 100 + 240 = 340

Let's look back.

First: unfold it.

Then: area of each face.

Then: add them all.

Last: check.

Answer
= SA = 100 + 60 + 60 + 60 + 60 = 340

Your turn

Try this one yourself, then check:

square pyramid, base 8, slant height 15
Show the answer
304

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