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Nets and surface area

Unfold it, the area of each face, add them all · Geometry · 20 problems, easy to harder

▶ Watch the first one solved

How we do it

  1. Unfold it
  2. Area of each face
  3. Add them all
  4. Check

The steps for Net of a box 4 by 3 by 2. Every solution names its steps, so you always know what comes next.

Worked examples

Net of a box 4 by 3 by 2 Easy

The question

Question: draw the net of a box 4 by 3 by 2, and find its surface area.

box 4 by 3 by 2

The surface area is the area of all the outside faces together.

A net shows every face flat.

surface area = all the faces added

1 Unfold it

We cut along some edges and fold it flat.

Matching faces have the same colour.

2 Area of each face

Top and bottom: 4 × 3 is 12.

= top and bottom: 4 × 3 = 12

Front and back: 4 × 2 is 8.

= front and back: 4 × 2 = 8

The two sides: 3 × 2 is 6.

= the two sides: 3 × 2 = 6

Careful!

Count every face in the net.

A box has 6 faces, not 3.

Careful: not 12 + 8 + 6 = 26 ✗

3 Add them all

We add all 6 faces: 52.

= SA = 12 + 12 + 8 + 8 + 6 + 6 = 52

4 Check

Let's check another way.

The faces come in pairs.

One of each: 12 plus 8 plus 6 is 26.

Times 2 is 52.

So the answer is right!

2 × (12 + 8 + 6) = 2 × 26 = 52

Let's look back.

First: unfold it.

Then: area of each face.

Then: add them all.

Last: check.

Answer
= SA = 12 + 12 + 8 + 8 + 6 + 6 = 52

▶ Watch it solved

Net of a triangular prism sides 3, 4, 5, length 10 Medium

The question

Question: draw the net of a triangular prism, sides 3, 4, 5, length 10, and find its surface area.

triangular prism, sides 3, 4, 5, length 10

The surface area is the area of all the outside faces together.

A net shows every face flat.

surface area = all the faces added

1 Unfold it

Flat: three rectangles in a row, and a triangle at each end.

2 Area of each face

The two triangles: half × 3 × 4 is 6.

= the two triangles: ½ × 3 × 4 = 6

The 3 by 10 rectangle: 3 × 10 is 30.

= the 3 by 10 rectangle: 3 × 10 = 30

The 4 by 10 rectangle: 4 × 10 is 40.

= the 4 by 10 rectangle: 4 × 10 = 40

The 5 by 10 rectangle: 5 × 10 is 50.

= the 5 by 10 rectangle: 5 × 10 = 50

Careful!

Count every face in the net.

There are two triangles, one at each end.

Careful: not 6 + 30 + 40 + 50 = 126 ✗

3 Add them all

We add all 5 faces: 132.

= SA = 6 + 6 + 30 + 40 + 50 = 132

4 Check

Let's check another way.

The three rectangles make one long strip: 12 by 10, that is 120.

Plus the two triangles, 12.

Together 132.

So the answer is right!

(3 + 4 + 5) × 10 + 2 × 6 = 120 + 12 = 132

Let's look back.

First: unfold it.

Then: area of each face.

Then: add them all.

Last: check.

Answer
= SA = 6 + 6 + 30 + 40 + 50 = 132

▶ Watch it solved

Net of a triangular prism sides 5, 12, 13, length 8 Harder

The question

Question: draw the net of a triangular prism, sides 5, 12, 13, length 8, and find its surface area.

triangular prism, sides 5, 12, 13, length 8

The surface area is the area of all the outside faces together.

A net shows every face flat.

surface area = all the faces added

1 Unfold it

Flat: three rectangles in a row, and a triangle at each end.

2 Area of each face

The two triangles: half × 5 × 12 is 30.

= the two triangles: ½ × 5 × 12 = 30

The 5 by 8 rectangle: 5 × 8 is 40.

= the 5 by 8 rectangle: 5 × 8 = 40

The 12 by 8 rectangle: 12 × 8 is 96.

= the 12 by 8 rectangle: 12 × 8 = 96

The 13 by 8 rectangle: 13 × 8 is 104.

= the 13 by 8 rectangle: 13 × 8 = 104

Careful!

Count every face in the net.

There are two triangles, one at each end.

Careful: not 30 + 40 + 96 + 104 = 270 ✗

3 Add them all

We add all 5 faces: 300.

= SA = 30 + 30 + 40 + 96 + 104 = 300

4 Check

Let's check another way.

The three rectangles make one long strip: 30 by 8, that is 240.

Plus the two triangles, 60.

Together 300.

So the answer is right!

(5 + 12 + 13) × 8 + 2 × 30 = 240 + 60 = 300

Let's look back.

First: unfold it.

Then: area of each face.

Then: add them all.

Last: check.

Answer
= SA = 30 + 30 + 40 + 96 + 104 = 300

▶ Watch it solved

Practice

Try each one, then open the answer. Stuck? Open the problem to watch every step.

Easy

  1. net of a box 4 by 3 by 2
    Answer
    = SA = 12 + 12 + 8 + 8 + 6 + 6 = 52
  2. net of a cube side 5
    Answer
    = SA = 25 + 25 + 25 + 25 + 25 + 25 = 150
  3. net of a box 5 by 2 by 1
    Answer
    = SA = 10 + 10 + 5 + 5 + 2 + 2 = 34
  4. net of a cube side 3
    Answer
    = SA = 9 + 9 + 9 + 9 + 9 + 9 = 54
  5. net of a box 6 by 4 by 3
    Answer
    = SA = 24 + 24 + 18 + 18 + 12 + 12 = 108
  6. net of a box 2 cm by 2 cm by 5 cm
    Answer
    = SA = 4 + 4 + 10 + 10 + 10 + 10 = 48 cm²
  7. net of a cube side 10 cm
    Answer
    = SA = 100 + 100 + 100 + 100 + 100 + 100 = 600 cm²

Medium

  1. net of a triangular prism sides 3, 4, 5, length 10
    Answer
    = SA = 6 + 6 + 30 + 40 + 50 = 132
  2. net of a square pyramid base 6, slant height 5
    Answer
    = SA = 36 + 15 + 15 + 15 + 15 = 96
  3. net of a box 10 by 5 by 4
    Answer
    = SA = 50 + 50 + 40 + 40 + 20 + 20 = 220
  4. net of a triangular prism sides 6, 8, 10, length 5
    Answer
    = SA = 24 + 24 + 30 + 40 + 50 = 168
  5. net of a square pyramid base 4, slant height 3
    Answer
    = SA = 16 + 6 + 6 + 6 + 6 = 40
  6. net of a box 8 m by 3 m by 2 m
    Answer
    = SA = 24 + 24 + 16 + 16 + 6 + 6 = 92 m²
  7. net of a square pyramid base 10, slant height 12
    Answer
    = SA = 100 + 60 + 60 + 60 + 60 = 340

Harder

  1. net of a triangular prism sides 5, 12, 13, length 8
    Answer
    = SA = 30 + 30 + 40 + 96 + 104 = 300
  2. net of a box 12 by 7 by 4
    Answer
    = SA = 84 + 84 + 48 + 48 + 28 + 28 = 320
  3. net of a square pyramid base 8 cm, slant height 9 cm
    Answer
    = SA = 64 + 36 + 36 + 36 + 36 = 208 cm²
  4. net of a triangular prism sides 3, 4, 5, length 2
    Answer
    = SA = 6 + 6 + 6 + 8 + 10 = 36
  5. net of a box 1 by 1 by 9
    Answer
    = SA = 1 + 1 + 9 + 9 + 9 + 9 = 38
  6. net of a triangular prism sides 9, 12, 15, length 6
    Answer
    = SA = 54 + 54 + 54 + 72 + 90 = 324