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Net of a square pyramid base 4, slant height 3

Step by step, with the reason for every step · Nets and surface area · Geometry

Step by step

The question

Question: draw the net of a square pyramid, base 4, slant height 3, and find its surface area.

square pyramid, base 4, slant height 3

The surface area is the area of all the outside faces together.

A net shows every face flat.

surface area = all the faces added

1 Unfold it

Flat: the square base, with a triangle on each side.

2 Area of each face

The square base: 4 × 4 is 16.

= the square base: 4 × 4 = 16

Each triangle: half × 4 × 3 is 6.

= each triangle: ½ × 4 × 3 = 6

Careful!

Count every face in the net.

There are four triangles.

Careful: not 16 + 6 = 22 ✗

3 Add them all

We add all 5 faces: 40.

= SA = 16 + 6 + 6 + 6 + 6 = 40

4 Check

Let's check another way.

Four triangles of half 4 times 3 are two whole 4 by 3 rectangles: 24.

Plus the base 16.

Together 40.

So the answer is right!

4 × 4 + 2 × 4 × 3 = 16 + 24 = 40

Let's look back.

First: unfold it.

Then: area of each face.

Then: add them all.

Last: check.

Answer
= SA = 16 + 6 + 6 + 6 + 6 = 40

Your turn

Try this one yourself, then check:

square pyramid, base 5, slant height 4
Show the answer
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