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Net of a square pyramid base 8 cm, slant height 9 cm

Step by step, with the reason for every step · Nets and surface area · Geometry

Step by step

The question

Question: draw the net of a square pyramid, base 8 cm, slant height 9 cm, and find its surface area.

square pyramid, base 8 cm, slant height 9 cm

The surface area is the area of all the outside faces together.

A net shows every face flat.

surface area = all the faces added

1 Unfold it

Flat: the square base, with a triangle on each side.

2 Area of each face

The square base: 8 × 8 is 64.

= the square base: 8 × 8 = 64

Each triangle: half × 8 × 9 is 36.

= each triangle: ½ × 8 × 9 = 36

Careful!

Count every face in the net.

There are four triangles.

Careful: not 64 + 36 = 100 ✗

3 Add them all

We add all 5 faces: 208 cm².

= SA = 64 + 36 + 36 + 36 + 36 = 208 cm²

4 Check

Let's check another way.

Four triangles of half 8 times 9 are two whole 8 by 9 rectangles: 144.

Plus the base 64.

Together 208.

So the answer is right!

8 × 8 + 2 × 8 × 9 = 64 + 144 = 208

Let's look back.

First: unfold it.

Then: area of each face.

Then: add them all.

Last: check.

Answer
= SA = 64 + 36 + 36 + 36 + 36 = 208 cm²

Your turn

Try this one yourself, then check:

square pyramid, base 8 cm, slant height 13 cm
Show the answer
272 cm²

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