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Normal: P(40 < X < 65), mean 50, sd 10

Step by step, with the reason for every step · Normal probabilities with the z-table · University Statistics

Step by step

The question

Question: X is normal, with mean 50 and SD 10: what is the probability that X is between 40 and 65?

P(40 < X < 65): μ = 50, σ = 10

μ is the mean.

σ is the standard deviation, the SD.

μ = the mean, σ = the SD

1 Find z

z counts how many SDs x is from the mean: x minus the mean, over the SD.

z = x − μσ

40 minus 50 is −10.

Divided by 10, that is −1.

z = 40 − 5010 = −1010 = −1

And for 65: 65 minus 50 is 15.

Divided by 10, that is 1.5.

z = 65 − 5010 = 1510 = 1.5

2 Draw and shade

The bell: the mean, 50, in the middle.

40 is left of it.

65 is right of it.

We want X between 40 and 65.

We shade that part.

3 Read the table

The z-table gives the area to the left of z.

For z = −1: 0.1587.

For z = 1.5: 0.9332.

4 The area we want

Careful!

Both table numbers start at the far left.

So we take away the smaller one.

Careful: between: big area − small area

Between them: the bigger area minus the smaller one.

0.9332 minus 0.1587 is 0.7745.

P(40 < X < 65) = 0.9332 − 0.1587 = 0.7745

5 Check

Let's check: the three parts of the bell.

Left of z = −1: 0.1587.

Right of z = 1.5: 1 minus 0.9332, 0.0668.

left 0.1587 + middle 0.7745 + right 0.0668

They add up to 1, the whole bell.

So it is right!

= 1.0000

Let's look back.

First: find z.

Then: draw and shade.

Then: read the table.

Then: the area we want.

Last: check.

Answer
P(40 < X < 65) = 0.9332 − 0.1587 = 0.7745

Your turn

Try this one yourself, then check:

Find P(50 < X < 100): μ = 70, σ = 20
Show the answer
P(50 < X < 100) = 0.7745

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