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Normal: P(X > 62), mean 50, sd 8

Step by step, with the reason for every step · Normal probabilities with the z-table · University Statistics

Step by step

The question

Question: X is normal, with mean 50 and SD 8: what is the probability that X is more than 62?

P(X > 62): μ = 50, σ = 8

μ is the mean.

σ is the standard deviation, the SD.

μ = the mean, σ = the SD

1 Find z

z counts how many SDs x is from the mean: x minus the mean, over the SD.

z = x − μσ

62 minus 50 is 12.

Divided by 8, that is 1.5.

z = 62 − 508 = 128 = 1.5

2 Draw and shade

The bell: the mean, 50, in the middle.

62 is right of it.

We want X more than 62.

We shade that part.

3 Read the table

The z-table gives the area to the left of z.

Row 1.5, column .00.

For z = 1.5: the row 1.5 and the column .00 meet at 0.9332.

4 The area we want

Careful!

0.9332 is the area to the left.

We want the right side.

Careful: not 0.9332 ✗

The whole bell is 1.

The right side is 1 minus the left: 1 minus 0.9332 is 0.0668.

P(X > 62) = 1 − 0.9332 = 0.0668

5 Check

Let's check another way.

The bell is the same on both sides.

So the area right of 1.5 is the area left of −1.5.

right of 1.5 = left of −1.5

The table at −1.5 gives 0.0668.

The same!

So it is right!

table at −1.5: 0.0668

Let's look back.

First: find z.

Then: draw and shade.

Then: read the table.

Then: the area we want.

Last: check.

Answer
P(X > 62) = 1 − 0.9332 = 0.0668

Your turn

Try this one yourself, then check:

Find P(X > 76): μ = 40, σ = 24
Show the answer
P(X > 76) = 0.0668

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