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Normal: P(X < 57), mean 50, sd 4

Step by step, with the reason for every step · Normal probabilities with the z-table · University Statistics

Step by step

The question

Question: X is normal, with mean 50 and SD 4: what is the probability that X is less than 57?

P(X < 57): μ = 50, σ = 4

μ is the mean.

σ is the standard deviation, the SD.

μ = the mean, σ = the SD

1 Find z

z counts how many SDs x is from the mean: x minus the mean, over the SD.

z = x − μσ

57 minus 50 is 7.

Divided by 4, that is 1.75.

z = 57 − 504 = 74 = 1.75

2 Draw and shade

The bell: the mean, 50, in the middle.

57 is right of it.

We want X less than 57.

We shade that part.

3 Read the table

The z-table gives the area to the left of z.

Row 1.7, column .05.

For z = 1.75: the row 1.7 and the column .05 meet at 0.9599.

4 The area we want

Careful!

The z-table always gives the area to the left of z.

Here that is what we want.

Careful: the table gives the area to the LEFT

Less than: the area to the left.

That is just the table number, 0.9599.

P(X < 57) = 0.9599

5 Check

Let's check another way.

The bell is the same on both sides.

So the area left of 1.75 is the area right of −1.75.

left of 1.75 = right of −1.75

1 minus the table at −1.75: 1 minus 0.0401 is 0.9599.

The same!

So it is right!

1 − table at −1.75: 1 − 0.0401 = 0.9599

Let's look back.

First: find z.

Then: draw and shade.

Then: read the table.

Then: the area we want.

Last: check.

Answer
P(X < 57) = 0.9599

Your turn

Try this one yourself, then check:

Find P(X < 38.5): μ = 35, σ = 2
Show the answer
P(X < 38.5) = 0.9599

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