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Normal: P(X > 40), mean 50, sd 10

Step by step, with the reason for every step · Normal probabilities with the z-table · University Statistics

Step by step

The question

Question: X is normal, with mean 50 and SD 10: what is the probability that X is more than 40?

P(X > 40): μ = 50, σ = 10

μ is the mean.

σ is the standard deviation, the SD.

μ = the mean, σ = the SD

1 Find z

z counts how many SDs x is from the mean: x minus the mean, over the SD.

z = x − μσ

40 minus 50 is −10.

Divided by 10, that is −1.

z = 40 − 5010 = −1010 = −1

2 Draw and shade

The bell: the mean, 50, in the middle.

40 is left of it.

We want X more than 40.

We shade that part.

3 Read the table

The z-table gives the area to the left of z.

Row −1.0, column .00.

For z = −1: the row −1.0 and the column .00 meet at 0.1587.

4 The area we want

Careful!

0.1587 is the area to the left.

We want the right side.

Careful: not 0.1587 ✗

The whole bell is 1.

The right side is 1 minus the left: 1 minus 0.1587 is 0.8413.

P(X > 40) = 1 − 0.1587 = 0.8413

5 Check

Let's check another way.

The bell is the same on both sides.

So the area right of −1 is the area left of 1.

right of −1 = left of 1

The table at 1 gives 0.8413.

The same!

So it is right!

table at 1: 0.8413

Let's look back.

First: find z.

Then: draw and shade.

Then: read the table.

Then: the area we want.

Last: check.

Answer
P(X > 40) = 1 − 0.1587 = 0.8413

Your turn

Try this one yourself, then check:

Find P(X > 20): μ = 30, σ = 10
Show the answer
P(X > 20) = 0.8413

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