Steply

Prove if n is a multiple of 3, then n^2 is a multiple of 9

Step by step, with the reason for every step · Direct proof · Discrete Math

Step by step

The question

Question: prove that if n is a multiple of 3, then n² is a multiple of 9.

1 Write it with letters

n is a multiple of 3, so n = 3a, where a is a whole number.

n = 3a

That is what a multiple of 3 means.

a multiple of 3 = 3 × a whole number

Careful!

An example shows one number.

The letters show every number at once.

Careful: one example is not a proof

2 Put them in

Now put them in: n² becomes (3a)².

n2 = (3a)2

3 Work it out

(3a)² means the bracket times itself.

= (3a)(3a)

Every part times every part: 9a².

= 9a2

4 Show the form

Every term has a 9 in it.

We take out 9: 9a².

= 9a2

a² is a whole number, because whole numbers added and multiplied stay whole.

a² is a whole number

9 times a whole number: so n² is a multiple of 9.

So n² is a multiple of 9. ∎

The square at the end means: the proof is done.

5 Check

An example: n = 3.

It gives 9.

n = 3: 3² = 9

9 is 9 times 1: a multiple of 9, as the proof says.

Right!

9 = 9 × 1

Let's look back.

First: write it with letters.

Then: put them in.

Then: work it out.

Then: show the form.

Last: check.

Answer
a² is a whole number

Your turn

Try this one yourself, then check:

Show the answer
n2 = 16a2

More from Direct proof

The whole lesson: Direct proof →