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Prove the sum of two consecutive odd numbers is a multiple of 4

Step by step, with the reason for every step · Direct proof · Discrete Math

Step by step

The question

Question: prove that the sum of two consecutive odd numbers is a multiple of 4.

1 Write it with letters

Call the first number 2a + 1: an odd number, where a is a whole number.

The next odd numbers are 2 more each time: 2a + 1 + 2.

the numbers = 2a + 1, 2a + 1 + 2
odd = 2 × a whole number + 1

Careful!

An example shows one number.

The letters show every number at once.

Careful: one example is not a proof

2 Put them in

Add them up.

sum = 2a + 1 + (2a + 1 + 2)

3 Work it out

Open the brackets: 2a + 1 + 2a + 1 + 2.

= 2a + 1 + 2a + 1 + 2

Like terms together: 4a + 4.

= 4a + 4

4 Show the form

Every term has a 4 in it.

We take out 4: 4(a + 1).

= 4(a + 1)

a + 1 is a whole number, because whole numbers added and multiplied stay whole.

a + 1 is a whole number

4 times a whole number: so the sum is a multiple of 4.

So the sum is a multiple of 4. ∎

The square at the end means: the proof is done.

5 Check

An example: 3, 5.

It gives 8.

3 + 5 = 8

8 is 4 times 2: a multiple of 4, as the proof says.

Right!

8 = 4 × 2

Let's look back.

First: write it with letters.

Then: put them in.

Then: work it out.

Then: show the form.

Last: check.

Answer
a + 1 is a whole number

Your turn

Try this one yourself, then check:

Show the answer
sum = 3(2a + 3)

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