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Samples of 81 from mean 45, sd 18: P(sample mean > 48.5)

Step by step, with the reason for every step · Sample means and the central limit theorem · University Statistics

Step by step

The question

Question: samples of 81 are taken from numbers with mean 45 and SD 18: what is the probability that the sample mean is more than 48.5?

P(x̄ > 48.5): μ = 45, σ = 18, n = 81

x̄, x bar, is the mean of one sample.

x̄ = the mean of one sample

1 The sample means

The central limit theorem: the means of many samples make a bell.

Its middle is the mean, 45.

Its SD is smaller: σ divided by the square root of n.

many samples of 81: their means make a bell
middle: μ = 45
SD of the means: σ ÷ √n

The square root of 81 is 9.

18 divided by 9 is 2.

σx̄ = σ√n = 18√81 = 189 = 2

Careful!

The sample means have SD 2, not 18.

So we divide by 2.

Careful: not z = 48.5 − 4518 ✗

2 Find z

z counts how many SDs the sample mean is from the mean: x̄ minus the mean, over the SD.

z = x̄ − μσx̄

48.5 minus 45 is 3.5.

Divided by 2, that is 1.75.

z = 48.5 − 452 = 3.52 = 1.75

3 Draw and shade

The bell: the mean, 45, in the middle.

48.5 is right of it.

We want the sample mean more than 48.5.

We shade that part.

4 Read the table

The z-table gives the area to the left of z.

Row 1.7, column .05.

For z = 1.75: the row 1.7 and the column .05 meet at 0.9599.

5 The area we want

The whole bell is 1.

The right side is 1 minus the left: 1 minus 0.9599 is 0.0401.

P(x̄ > 48.5) = 1 − 0.9599 = 0.0401

6 Check

Let's check another way.

The bell is the same on both sides.

So the area right of 1.75 is the area left of −1.75.

right of 1.75 = left of −1.75

The table at −1.75 gives 0.0401.

The same!

So it is right!

table at −1.75: 0.0401

Let's look back.

First: the sample means.

Then: find z.

Then: draw and shade.

Then: read the table.

Then: the area we want.

Last: check.

Answer
P(x̄ > 48.5) = 1 − 0.9599 = 0.0401

Your turn

Try this one yourself, then check:

Find P(x̄ > 72): μ = 65, σ = 36, n = 81
Show the answer
P(x̄ > 72) = 0.0401

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