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Solve 2x - 1 > 2 and x < 4

Step by step, with the reason for every step · Compound inequalities with and / or · Algebra 1

Step by step

The question

Question: solve 2x − 1 > 2 and x < 4.

"And" means both parts must be true.

2x − 1 > 2 and x < 4
and: both true

1 Solve the first part

First part: 2x − 1 > 2.

2x − 1 > 2

We want x by itself.

Two things are stuck to x: times 2 and − 1.

The − 1 is on the outside, so it comes off first.

Then the times 2.

To remove − 1, we add 1.

We do it on both sides, so the sign stays true.

2x − 1 + 1 > 2 + 1

− 1 and + 1 make zero.

Cross them out.

2 + 1 = 3.

2 + 1 = 3

Now we have 2x > 3.

2x > 3

2x means 2 times x.

We want just x.

To remove times 2, we divide by 2.

We do it on both sides, so the sign stays true.

2x2 > 32

2 divided by 2 is 1.

So just x is left.

So x is greater than 3/2.

x > 32

2 Show each part on a number line

3 Find the numbers in both

"And": we keep only the numbers that are shaded on both lines.

So 3/2 < x < 4.

x is between 3/2 and 4.

= 32 < x < 4

Careful!

A number that is shaded on only one line is not an answer.

It must be on both.

Careful: and: only where BOTH lines are shaded

Books also write the answer like this.

It is called interval notation.

A round bracket means the end is not in, like the open circle.

interval: (32, 4)

4 Check

Let's test one number from the answer: 3.

"And": it must work in both parts.

First part.

First: 2(3) − 1 = 6 − 1 = 5

5 is greater than 2.

True!

5 > 2

Now the second part.

Second: 3

3 is less than 4.

True!

So the answer works.

3 < 4

Let's look back.

First: solve the first part.

Then: show each part on a number line.

Then: find the numbers in both.

Last: check.

Answer
Careful: and: only where BOTH lines are shaded

Your turn

Try this one yourself, then check:

Solve 2x − 1 > 0 and x < 3
Show the answer
12 < x < 3

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