Steply

Solve 3^x = 20

Step by step, with the reason for every step · Exponential equations and logarithms · Algebra 2

Step by step

The question

Question: solve 3ˣ = 20.

x is up in the power.

3x = 20

1 Compare with powers of 3

3² is 9, and 3³ is 27.

20 is between them.

So x is between 2 and 3: not a whole number.

3² = 9
3³ = 27

2 Take the log of both sides

Logs can bring a power down.

So we take the log of both sides.

We do it on both sides, so they stay equal.

log(3x) = log 20

3 Bring the power down

The power rule for logs: the power comes down in front, as times.

log(an) = n × log a

So log of 3ˣ is x times log 3.

x × log 3 = log 20

4 Remove the log 3

x times log 3.

To remove times log 3, we divide by log 3.

We do it on both sides, so they stay equal.

x × log 3log 3 = log 20log 3

log 3 divided by log 3 is 1.

So just x is left.

So x = log 20 over log 3.

This is the exact answer.

x = log 20log 3

5 Use a calculator

With a calculator: log 20 is about 1.3010.

Log 3 is about 0.4771.

log 20 ≈ 1.3010
log 3 ≈ 0.4771

1.3010 divided by 0.4771 is about 2.727.

x ≈ 2.727

So x is about 2.727, to three decimal places.

It is between 2 and 3, as we said.

6 Check

Let's check with a calculator: 3 to the power 2.727 is about 20.0.

That is 20.

It works!

Check: 32.727 ≈ 20.0

Let's look back.

First: compare with powers of 3.

Then: take the log of both sides.

Then: bring the power down.

Then: remove the log 3.

Then: use a calculator.

Last: check.

Answer
x ≈ 2.727

Your turn

Try this one yourself, then check:

Solve 3x = 7
Show the answer
x ≈ 1.771

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