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Solve 5^(2x - 1) = 125

Step by step, with the reason for every step · Exponential equations and logarithms · Algebra 2

Step by step

The question

Question: solve 5 to the power (2x − 1) = 125.

x is up in the power.

52x − 1 = 125

1 Write 125 as a power of 5

125 is 5 times itself, 3 times.

5 × 5 × 5 = 125

So 125 is 5³.

Now both sides are 5 to a power.

52x − 1 = 53

2 The powers are equal

Both sides are 5 to a power.

Same base, and they are equal.

So the powers must be equal too.

same base → same power

Now we have 2x − 1 = 3.

2x − 1 = 3

We want x by itself.

Two things are stuck to x: times 2 and − 1.

The − 1 is on the outside, so it comes off first.

Then the times 2.

3 Remove the − 1

To remove − 1, we add 1.

We do it on both sides.

Why both sides?

The = sign means both sides are the same amount.

If we change only one side, they are not the same any more.

2x − 1 + 1 = 3 + 1

− 1 and + 1 make zero.

Cross them out.

3 + 1 = 4.

3 + 1 = 4

Now we have 2x = 4.

2x = 4

4 Remove the 2

2x means 2 times x.

We want just x.

To remove times 2, we divide by 2.

We do it on both sides, so they stay equal.

2x2 = 42

2 divided by 2 is 1.

So just x is left.

4 divided by 2 is 2.

42 = 2

So x = 2!

x = 2

5 Check

Let's check: put 2 in place of x.

Check: 52(2) − 1 = 54 − 1 = 53 = 125

We get 125, the same as the right side.

So x = 2 is right!

Let's look back.

First: write 125 as a power of 5.

Then: the powers are equal.

Then: remove the − 1.

Then: remove the 2.

Last: check.

Answer
x = 2

Your turn

Try this one yourself, then check:

Solve 22x − 2 = 16
Show the answer
x = 3

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