Steply

Solve f(x) = (x^2 - 1)/(x - 1) for x != 1, 2 for x = 1, continuous…

Step by step, with the reason for every step · Continuity · Calculus

Step by step

The question

Question: decide if this f(x) is continuous at x = 1.

f(x) = x2 − 1x − 1 if x ≠ 1
= 2 if x = 1

Continuous at x = 1 means three things are true.

One: f(1) has a value.

Two: the limit there exists.

Three: they are equal.

1. f(1) has a value
2. the limit at 1 exists
3. limit = f(1)

1 Does f have a value?

Which piece holds x = 1?

The one with x = 1.

So f(1) = 2.

f(1) = 2

Careful!

Having a value is not enough.

The graph must also arrive at that height from both sides.

Careful: a value at 1 is not enough

Check 1 is true: f(1) is 2.

1. f(1) = 2

2 Does the limit exist?

Near 1, but not at 1, f(x) is (x² − 1)/(x − 1).

Factor the top and the bottom.

lim x → 1 f(x) = lim x → 1 (x − 1)(x + 1)(x − 1)

x is never 1 here, so x − 1 is not 0.

Cross it out on the top and the bottom.

Put 1 in what is left.

The limit is 2.

= lim x → 1 (x + 1) = 2

Check 2 is true: the limit exists.

2. limit = 2

3 Are they equal?

The limit is 2, and f(1) is 2.

They are equal.

Check 3 is true.

3. limit = 2 = f(1)

All three checks are true.

So f is continuous at x = 1.

= f is continuous at x = 1

4 Check

Let's check on the graph.

The graph comes to height 2 from both sides, but there is a hole at x = 1.

f(1) = 2 fills the hole.

No lifting the pen.

Right!

Let's look back.

First: does f have a value?.

Then: does the limit exist?.

Then: are they equal?.

Last: check.

Answer
= f is continuous at x = 1

Your turn

Try this one yourself, then check:

f(x) = x2 − 3xx − 3 if x ≠ 3; 3 if x = 3
Show the answer
continuous at x = 3

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