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Solve f(x) = (x^2 - 9)/(x + 3) for x != -3, 0 for x = -3, continuous…

Step by step, with the reason for every step · Continuity · Calculus

Step by step

The question

Question: decide if this f(x) is continuous at x = −3.

f(x) = x2 − 9x + 3 if x ≠ −3
= 0 if x = −3

Continuous at x = −3 means three things are true.

One: f(−3) has a value.

Two: the limit there exists.

Three: they are equal.

1. f(−3) has a value
2. the limit at −3 exists
3. limit = f(−3)

1 Does f have a value?

Which piece holds x = −3?

The one with x = −3.

So f(−3) = 0.

f(−3) = 0

Careful!

Having a value is not enough.

The graph must also arrive at that height from both sides.

Careful: a value at −3 is not enough

Check 1 is true: f(−3) is 0.

1. f(−3) = 0

2 Does the limit exist?

Near −3, but not at −3, f(x) is (x² − 9)/(x + 3).

Factor the top and the bottom.

lim x → −3 f(x) = lim x → −3 (x + 3)(x − 3)(x + 3)

x is never −3 here, so x + 3 is not 0.

Cross it out on the top and the bottom.

Put −3 in what is left.

The limit is −6.

= lim x → −3 (x − 3) = −6

Check 2 is true: the limit exists.

2. limit = −6

3 Are they equal?

The limit is −6, but f(−3) is 0.

They are not equal.

Check 3 is false.

3. limit −6 ≠ f(−3) = 0 ✗

So f is not continuous at x = −3.

= f is not continuous at x = −3

4 Check

Let's check on the graph.

The graph comes to height −6 from both sides, but there is a hole at x = −3.

f(−3) = 0 is a dot somewhere else.

We must lift the pen.

Right!

Let's look back.

First: does f have a value?.

Then: does the limit exist?.

Then: are they equal?.

Last: check.

Answer
= f is not continuous at x = −3

Your turn

Try this one yourself, then check:

f(x) = x2 − 2x − 8x + 2 if x ≠ −2; −3 if x = −2
Show the answer
not continuous at x = −2

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