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Solve log_3(2x + 1) = 2

Step by step, with the reason for every step · Exponential equations and logarithms · Algebra 2

Step by step

The question

Question: solve log₃(2x + 1) = 2.

log3(2x + 1) = 2

1 Write it as a power

A log is a power.

log₃(2x + 1) = 2 means: 3 to the power 2 is 2x + 1.

log3 c = k means 3k = c

So 2x + 1 is 3².

2x + 1 = 32

2 Work out the power

3 times 3 is 9.

3 × 3 = 9

Now we have 2x + 1 = 9.

2x + 1 = 9

We want x by itself.

Two things are stuck to x: times 2 and + 1.

The + 1 is on the outside, so it comes off first.

Then the times 2.

3 Remove the + 1

To remove + 1, we take away 1.

We do it on both sides.

Why both sides?

The = sign means both sides are the same amount.

If we change only one side, they are not the same any more.

2x + 1 − 1 = 9 − 1

+ 1 and − 1 make zero.

Cross them out.

9 − 1 = 8.

9 − 1 = 8

Now we have 2x = 8.

2x = 8

4 Remove the 2

2x means 2 times x.

We want just x.

To remove times 2, we divide by 2.

We do it on both sides, so they stay equal.

2x2 = 82

2 divided by 2 is 1.

So just x is left.

8 divided by 2 is 4.

82 = 4

So x = 4!

x = 4

5 Check

Let's check: put 4 in place of x.

Check: log3(2(4) + 1) = log3(8 + 1) = log3 9

log₃ 9 is 2, because 3² is 9.

So x = 4 is right!

log3 9 = 2, because 32 = 9

Let's look back.

First: write it as a power.

Then: work out the power.

Then: remove the + 1.

Then: remove the 2.

Last: check.

Answer
x = 4

Your turn

Try this one yourself, then check:

log3(2x + 1) = 1
Show the answer
x = 1

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