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Solve x + 3 > 1 or 2x < 4

Step by step, with the reason for every step · Compound inequalities with and / or · Algebra 1

Step by step

The question

Question: solve x + 3 > 1 or 2x < 4.

"Or" means one of the parts is enough.

x + 3 > 1 or 2x < 4
or: one is enough

1 Solve the first part

First part: x + 3 > 1.

x + 3 > 1

We want x by itself.

The + 3 is in the way.

To remove + 3, we take away 3.

We do it on both sides, so the sign stays true.

x + 3 − 3 > 1 − 3

+ 3 and − 3 make zero.

Cross them out.

1 − 3 = −2.

1 − 3 = −2

So x is greater than −2.

x > −2

2 Solve the second part

Second part: 2x < 4.

2x < 4

2x means 2 times x.

We want just x.

To remove times 2, we divide by 2.

We do it on both sides, so the sign stays true.

2x2 < 42

2 divided by 2 is 1.

So just x is left.

4 divided by 2 is 2.

42 = 2

So x is less than 2.

x < 2

3 Show each part on a number line

4 Put the parts together

Every number is shaded on at least one line.

Every number is in one of the parts.

So every number works.

Every number is in one of the parts.

Let's look back.

First: solve the first part.

Then: solve the second part.

Then: show each part on a number line.

Last: put the parts together.

Answer
Every number is in one of the parts.

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