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Surface area of triangular prism sides 3 m, 4 m, 5 m length 2 m

Step by step, with the reason for every step · Prisms · Geometry

Step by step

The question

Question: find the surface area of a triangular prism with triangle sides 3 m, 4 m and 5 m, and length 2 m.

1 Count the faces

The surface area is the area of all the outside faces.

This prism has 5 faces: 2 triangles and 3 rectangles.

2 The two triangles

Is there a right angle?

3 squared plus 4 squared is 9 plus 16, which is 25.

That is 5 squared.

So yes: the triangle has a right angle.

So its two short sides are its base and height: 4 m and 3 m.

One triangle is half of base times height: ½ × 4 × 3.

triangle = 12 × 4 × 3

4 times 3 is 12.

triangle = 12 × 12

Half of 12 means 12 divided by 2.

That is 6.

122 = 6

So one triangle is 6 m².

triangle = 6 m2

The back is the same.

Two triangles: 2 times 6 is 12.

2 triangles = 2 × 6 = 12 m2

3 The three rectangles

The bottom rectangle is 4 by 2.

This one is 5 by 2.

And this one is 3 by 2.

Unroll the three rectangles side by side.

They make one long rectangle: 4 + 5 + 3 wide and 2 long.

So the rectangles are around the triangle, times the length.

rectangles = (4 + 5 + 3) × 2

4 plus 5 plus 3 is 12.

rectangles = 12 × 2

12 times 2 is 24.

So the rectangles are 24 m².

rectangles = 24 m2

4 Add all the faces

Add the triangles and the rectangles: 12 + 24.

S = 12 + 24

12 plus 24 is 36.

So the surface area is 36 m².

S = 36 m2

Let's look back.

First: count the faces.

Then: the two triangles.

Then: the three rectangles.

Last: add all the faces.

Answer
S = 36 m2

Your turn

Try this one yourself, then check:

Find the surface area.
Show the answer
S = 60 m2

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