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Surface area of triangular prism sides 6 cm, 8 cm, 10 cm length 5 cm

Step by step, with the reason for every step · Prisms · Geometry

Step by step

The question

Question: find the surface area of a triangular prism with triangle sides 6 cm, 8 cm and 10 cm, and length 5 cm.

1 Count the faces

The surface area is the area of all the outside faces.

This prism has 5 faces: 2 triangles and 3 rectangles.

2 The two triangles

Is there a right angle?

6 squared plus 8 squared is 36 plus 64, which is 100.

That is 10 squared.

So yes: the triangle has a right angle.

So its two short sides are its base and height: 8 cm and 6 cm.

One triangle is half of base times height: ½ × 8 × 6.

triangle = 12 × 8 × 6

8 times 6 is 48.

triangle = 12 × 48

Half of 48 means 48 divided by 2.

That is 24.

482 = 24

So one triangle is 24 cm².

triangle = 24 cm2

The back is the same.

Two triangles: 2 times 24 is 48.

2 triangles = 2 × 24 = 48 cm2

3 The three rectangles

The bottom rectangle is 8 by 5.

This one is 10 by 5.

And this one is 6 by 5.

Unroll the three rectangles side by side.

They make one long rectangle: 8 + 10 + 6 wide and 5 long.

So the rectangles are around the triangle, times the length.

rectangles = (8 + 10 + 6) × 5

8 plus 10 plus 6 is 24.

rectangles = 24 × 5

24 times 5 is 120.

So the rectangles are 120 cm².

rectangles = 120 cm2

4 Add all the faces

Add the triangles and the rectangles: 48 + 120.

S = 48 + 120

48 plus 120 is 168.

So the surface area is 168 cm².

S = 168 cm2

Let's look back.

First: count the faces.

Then: the two triangles.

Then: the three rectangles.

Last: add all the faces.

Answer
S = 168 cm2

Your turn

Try this one yourself, then check:

Find the surface area.
Show the answer
S = 36 cm2

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