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Unit vector of <8, 15>

Step by step, with the reason for every step · Magnitude and direction, unit vector · Precalculus

Step by step

The question

Question: find the unit vector in the direction of v = ⟨8, 15⟩.

v = ⟨8, 15⟩

1 Draw the arrow

Draw the grid.

The arrow starts at the origin.

It goes right 8 and up 15.

Across 8 and up 15 make a right triangle.

2 Find the length

The length ‖v‖: the long side of the right triangle.

Pythagoras: square the two parts, add them, then take the square root.

‖v‖ = √82 + 152

Write the squares: 64 + 225.

‖v‖ = √64 + 225

64 plus 225 is 289.

‖v‖ = √289

17 times 17 is 289.

17 × 17 = 289

So ‖v‖ = 17.

‖v‖ = 17

3 Divide by the length

To make the length 1, divide each part by the length, 17.

The direction stays the same.

u = ⟨817, 1517⟩

Careful!

Not 1 in each part.

The length must be 1, and the arrow must point the same way as v.

Careful: not ⟨1, 1⟩ ✗

So u = ⟨8/17, 15/17⟩.

u = ⟨817, 1517⟩

On the grid, u is a short arrow along v: length 1.

4 Check

Let's check: the length of u must be 1.

Square the parts and add them.

(817)2 + (1517)2 = 64289 + 225289 = 289289 = 1

We get 1.

So the length of u is 1.

Right!

Let's look back.

First: draw the arrow.

Then: find the length.

Then: divide by the length.

Last: check.

Answer
u = ⟨817, 1517⟩

Your turn

Try this one yourself, then check:

Find the unit vector in the direction of v⟨4, 3⟩
Show the answer
u = ⟨45, 35⟩

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