Steply

Unit vector of <-4, 4, 2>

Step by step, with the reason for every step · Vectors in space · Calculus 3

Step by step

The question

Question: find the unit vector in the direction of v = ⟨−4, 4, 2⟩.

v = ⟨−4, 4, 2⟩

1 Find the length

The length ‖v‖ is Pythagoras with three parts.

Square each part, add, then take the square root.

‖v‖ = √(−4)2 + 42 + 22

(−4) squared is 16.

4 squared is 16.

2 squared is 4.

Minus times minus is plus.

‖v‖ = √16 + 16 + 4

Add: 16 plus 16 plus 4 is 36.

‖v‖ = √36

6 times 6 is 36.

6 × 6 = 36

So ‖v‖ = 6.

‖v‖ = 6

2 Divide by the length

To make the length 1, we divide the vector by its own length.

Then it keeps its direction.

u = v‖v‖
length ÷ length = 1

Divide each part by 6.

u = ⟨−46, 46, 26⟩

Make the fractions simpler where we can.

u = ⟨−23, 23, 13⟩

So the unit vector is u = ⟨−2/3, 2/3, 1/3⟩.

u = ⟨−23, 23, 13⟩

Careful!

We divide by the length.

We don't take it away.

Careful: not ⟨−4, 4, 2⟩ − 6 ✗

3 Check

Let's check: the length of u.

Square each part: over 36.

They add up to 36/36, which is 1.

Right!

‖u‖ = √(16/36 + 16/36 + 4/36) = √(36/36) = 1

And every part has the same sign as in v, so it points the same way.

Right!

same signs as v → same direction

Let's look back.

First: find the length.

Then: divide by the length.

Last: check.

Answer
Careful: not ⟨−4, 4, 2⟩ − 6 ✗

Your turn

Try this one yourself, then check:

Find the unit vector in the direction of v = ⟨−2, 2, 1⟩
Show the answer
u = ⟨−23, 23, 13⟩

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