Steply

Unit vector of <-5, 12>

Step by step, with the reason for every step · Magnitude and direction, unit vector · Precalculus

Step by step

The question

Question: find the unit vector in the direction of v = ⟨−5, 12⟩.

v = ⟨−5, 12⟩

1 Draw the arrow

Draw the grid.

The arrow starts at the origin.

It goes left 5 and up 12.

Across 5 and up 12 make a right triangle.

2 Find the length

The length ‖v‖: the long side of the right triangle.

Pythagoras: square the two parts, add them, then take the square root.

‖v‖ = √(−5)2 + 122

Write the squares: 25 + 144.

‖v‖ = √25 + 144

25 plus 144 is 169.

‖v‖ = √169

13 times 13 is 169.

13 × 13 = 169

So ‖v‖ = 13.

‖v‖ = 13

3 Divide by the length

To make the length 1, divide each part by the length, 13.

The direction stays the same.

u = ⟨−513, 1213⟩

Careful!

Not 1 in each part.

The length must be 1, and the arrow must point the same way as v.

Careful: not ⟨1, 1⟩ ✗

So u = ⟨−5/13, 12/13⟩.

u = ⟨−513, 1213⟩

On the grid, u is a short arrow along v: length 1.

4 Check

Let's check: the length of u must be 1.

Square the parts and add them.

(−513)2 + (1213)2 = 25169 + 144169 = 169169 = 1

We get 1.

So the length of u is 1.

Right!

Let's look back.

First: draw the arrow.

Then: find the length.

Then: divide by the length.

Last: check.

Answer
u = ⟨−513, 1213⟩

Your turn

Try this one yourself, then check:

Find the unit vector in the direction of v⟨−3, 4⟩
Show the answer
u = ⟨−35, 45⟩

More from Magnitude and direction, unit vector

The whole lesson: Magnitude and direction, unit vector →