Steply

Which conic is 4x^2 + 9y^2 = 36

Step by step, with the reason for every step · Conics from the general form · Precalculus

Step by step

The question

Question: name the conic and write in standard form 4x² + 9y² − 36 = 0.

4x2 + 9y2 − 36 = 0

1 Name the conic

Look at the squares.

x² and y² have the same sign, but 4 and 9 are different numbers.

So it is an ellipse.

only x² or only y² → parabola
x² and y², same number in front → circle
same signs, different numbers → ellipse ✓
different signs → hyperbola

2 Move the number

Move the plain number to the right: − 36 becomes + 36.

4x2 + 9y2 = 36

3 Make the right side 1

Divide every part by 36, so the right side is 1.

4/36 is 1/9.

9/36 is 1/4.

x29 + y24 = 1
36 ÷ 4 = 9, 36 ÷ 9 = 4

That is the standard form of an ellipse with center (0, 0).

ellipse: center (0, 0)

4 Check

Let's check with a point on it: (3, 0), a vertex.

Put it in the first equation.

4 × 3² + 9 × 0² − 36 = 36 + 0 − 36 = 0

We get 0, like the first equation says.

So the standard form is right!

Let's look back.

First: name the conic.

Then: move the number.

Then: make the right side 1.

Last: check.

Answer
36 ÷ 4 = 9, 36 ÷ 9 = 4

Your turn

Try this one yourself, then check:

Name the conic and write in standard form 9x2 + 16y2 − 144 = 0
Show the answer
x216 + y29 = 1

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