Steply

Which conic is x^2 - y^2 - 4x - 5 = 0

Step by step, with the reason for every step · Conics from the general form · Precalculus

Step by step

The question

Question: name the conic and write in standard form x² − y² − 4x − 5 = 0.

x2 − y2 − 4x − 5 = 0

1 Name the conic

Look at the squares.

x² and y² have different signs.

So it is a hyperbola.

only x² or only y² → parabola
x² and y², same number in front → circle
same signs, different numbers → ellipse
different signs → hyperbola ✓

2 Group x and y

Put the x terms together in a bracket, and the y terms together.

(x2 − 4x) − y2 − 5 = 0

Move the plain number to the right: − 5 becomes + 5.

(x2 − 4x) − y2 = 5

3 Complete the square for x

Half of −4 is −2.

(−2) times (−2) is 4.

We add 4 inside the bracket.

So we add 4 on the right too.

(x2 − 4x + 4) − y2 = 5 + 4
−4 ÷ 2 = −2, (−2) × (−2) = 4

Careful!

What we add on the left, we add on the right too.

Then the two sides stay equal.

Careful: add 4 on both sides

4 Write as squares

Each bracket is now a full square.

On the right, 5 + 4 is 9.

(x − 2)2 − y2 = 9

5 Make the right side 1

Divide every part by 9, so the right side is 1.

(x − 2)29 − y29 = 1
9 ÷ 1 = 9, 9 ÷ −1 = -9

That is the standard form of a hyperbola with center (2, 0).

hyperbola: center (2, 0)

6 Check

Let's check with a point on it: (5, 0), a vertex.

Put it in the first equation.

5² − 0² − 4 × 5 − 5 = 25 + 0 − 20 − 5 = 0

We get 0, like the first equation says.

So the standard form is right!

Let's look back.

First: name the conic.

Then: group x and y.

Then: complete the square for x.

Then: write as squares.

Then: make the right side 1.

Last: check.

Answer
9 ÷ 1 = 9, 9 ÷ −1 = -9

Your turn

Try this one yourself, then check:

Name the conic and write in standard form x2 − y2 − 6x + 8 = 0
Show the answer
(x − 3)2 − y2 = 1

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