Step by step
The question
Question: name the conic and write in standard form x² − 4y² − 4 = 0.
x2 − 4y2 − 4 = 0
1 Name the conic
Look at the squares.
x² and y² have different signs.
So it is a hyperbola.
only x² or only y² → parabola
x² and y², same number in front → circle
same signs, different numbers → ellipse
different signs → hyperbola ✓
2 Move the number
Move the plain number to the right: − 4 becomes + 4.
x2 − 4y2 = 4
3 Make the right side 1
Divide every part by 4, so the right side is 1.
4/4 is 1/1.
x24 − y2 = 1
4 ÷ 1 = 4, 4 ÷ −4 = -1
That is the standard form of a hyperbola with center (0, 0).
hyperbola: center (0, 0)
4 Check
Let's check with a point on it: (2, 0), a vertex.
Put it in the first equation.
2² − 4 × 0² − 4 = 4 + 0 − 4 = 0
We get 0, like the first equation says.
So the standard form is right!
Let's look back.
First: name the conic.
Then: move the number.
Then: make the right side 1.
Last: check.
Answer
4 ÷ 1 = 4, 4 ÷ −4 = -1