Steply

Which conic is 9x^2 + 16y^2 = 144

Step by step, with the reason for every step · Conics from the general form · Precalculus

Step by step

The question

Question: name the conic and write in standard form 9x² + 16y² − 144 = 0.

9x2 + 16y2 − 144 = 0

1 Name the conic

Look at the squares.

x² and y² have the same sign, but 9 and 16 are different numbers.

So it is an ellipse.

only x² or only y² → parabola
x² and y², same number in front → circle
same signs, different numbers → ellipse ✓
different signs → hyperbola

2 Move the number

Move the plain number to the right: − 144 becomes + 144.

9x2 + 16y2 = 144

3 Make the right side 1

Divide every part by 144, so the right side is 1.

9/144 is 1/16.

16/144 is 1/9.

x216 + y29 = 1
144 ÷ 9 = 16, 144 ÷ 16 = 9

That is the standard form of an ellipse with center (0, 0).

ellipse: center (0, 0)

4 Check

Let's check with a point on it: (4, 0), a vertex.

Put it in the first equation.

9 × 4² + 16 × 0² − 144 = 144 + 0 − 144 = 0

We get 0, like the first equation says.

So the standard form is right!

Let's look back.

First: name the conic.

Then: move the number.

Then: make the right side 1.

Last: check.

Answer
144 ÷ 9 = 16, 144 ÷ 16 = 9

Your turn

Try this one yourself, then check:

Name the conic and write in standard form 4x2 + 9y2 − 36 = 0
Show the answer
x29 + y24 = 1

More from Conics from the general form

The whole lesson: Conics from the general form →