Step by step
The question
Question: 6, 9, 14, 21, 30, …: find the rule for term n.
1 First differences
We write the terms in a row.
Under each gap, the jump from one term to the next: 3, 5, 7, 9.
The jumps are not all the same.
So this is not an arithmetic sequence.
2 Second differences
Now the jumps of the jumps: 2 every time.
They are the same.
The same second difference means the rule has n squared in it.
A list like this is a quadratic sequence.
Why?
Look at n squared itself: 1, 4, 9, 16.
The jumps are 3, 5, 7, and their jumps are 2, 2.
The same every time.
3 Find a
The number in front of n squared is a.
One n squared gives a second difference of 2.
We have 2.
How many lots of 2 is that?
2 divided by 2 is 1.
Careful!
a is not the second difference itself.
It is half of it.
The right way: a = 2/2 = 1.
4 Take away n²
A table: n is the term number.
Under each term: n squared.
1, 4, 9 and so on.
Take it away from each term: once the n² part is gone, what is left is a simple list.
What is left: 5, 5, 5, 5, 5.
5 The linear part
What is left is 5 every time.
So that part is just 5.
6 Put it together
The rule is n squared, plus what was left: n² + 5.
7 Check
Let's check the rule with n = 1, 2 and 3.
We get 6, 9, 14: the first terms of the list.
So the rule is right!
Let's look back.
First: first differences.
Then: second differences.
Then: find a.
Then: take away n².
Then: the linear part.
Then: put it together.
Last: check.