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2 cards are dealt from 52, P(both aces)

Step by step, with the reason for every step · Probability with counting · Probability

Step by step

The question

Question: 2 cards are dealt from a deck of 52.

What is the probability that both are aces?

The probability is the number of ways we want, over all the ways.

P(all aces) = ways we wantall ways

P stands for probability.

P = probability

1 Order: yes or no

Does order matter?

No.

A hand of cards is the same hand in any order.

So we count groups: combinations.

= a hand: order does not matter → nCr

2 Count all the ways

52 C 2: the top 2 numbers from 52 down, over 2 factorial.

all = 52C2 = 52 × 512 × 1

Before we multiply, we make the numbers smaller.

52 on top and 2 at the bottom: 52 divided by 2 is 26.

What is left: 26 times 51.

That is 1326 ways.

all = 1326
26 × 51 = 1326

3 Count the ways we want

4 C 2: the top 2 numbers from 4 down, over 2 factorial.

aces = 4C2 = 4 × 32 × 1

Before we multiply, we make the numbers smaller.

4 on top and 2 at the bottom: 4 divided by 2 is 2.

What is left: 2 times 3.

That is 6 ways.

aces = 6
2 × 3 = 6

4 Write the fraction

6 ways we want, out of 1326.

P(all aces) = 61326

Careful!

The top and the bottom must count the same way: both are groups, with C.

Careful: count groups on top AND at the bottom

5 Simplify

Both 6 and 1326 can be divided by 6.

That makes it simpler.

P(all aces) = 6 ÷ 61326 ÷ 6

So it is 1/221.

P(all aces) = 1221

6 Check

Let's check another way: pick one at a time.

The first card: 4 out of 52.

Then one fewer each time.

Multiplied, that is 1/221.

The same.

So the answer is right!

452 × 351 = 1221

Let's look back.

First: order: yes or no.

Then: count all the ways.

Then: count the ways we want.

Then: write the fraction.

Then: simplify.

Last: check.

Answer
P(all aces) = 1221

Your turn

Try this one yourself, then check:

Show the answer
P(all clubs) = 117

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